Eleven equal point charges, all of then having a charge +Q , are placed at all the hour positions of a circular clock of radius r, except at the 10 hour position . What is the electric field strength at the centre of the clock ?

Eleven equal point charges, all of then having a charge +Q , are place

1.	Eleven equal point charges, all of then having a charge +Q , are placed at all the hour positions of a circular clock of radius r, except at the 10 hour position . What is the electric field strength at the centre of the clock ?
Answer» `(Q)/(4piepsilon_(0)r^(2))` from the CENTRE towards the mark 10 `(Q)/(4piepsilon_(0)r^(2))` from the mark 10towards the centre `(Q)/(4piepsilon_(0)r^(2))` from the centre towards the mark 6 Zero Solution :Given,radius of the circular clock = r and each of ELEVEN position of a circular clock has a charge +Q. `THEREFORE` Electric field at the centre of the clock is `E_(0)=E_(1)+E_(2)+E_(3)+E_(4)+E_(5)+E_(6)+E_(7)+E_(8)+E_(9)+E_(10)+E_(11)+E_(12)` Now , `E_(1)andE_(7)`are opposite to each other , so they will cancel out each OTHERS effect. Similarly`E_(2)andE_(8),E_(3)andE_(9),E_(5)andE_(11),E_(6)andE_(12)`will also cancel out their effect as they are opposite to each other. `thereforeE_(c)=E_(4)=(1)/(4piepsilon_(0))(Q)/(r^(2))` (directed from the centre towards the maek 10)

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Eleven equal point charges, all of then having a charge +Q , are placed at all the hour positions of a circular clock of radius r, except at the 10 hour position . What is the electric field strength at the centre of the clock ?

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