1.

Elimination of bromine from 2-bromobutane results in the formation of

Answer»

equimolar mixture of 1 and 2-butene
PREDOMINANTLY 2-butene
predominantly 1-butene
predominantly 2-butyne

Solution :`overset(beta)(H_(3))underset(Br)underset(|)overset(ALPHA)(C) - C overset(beta)(H) - CH_(2) - CH_(3) underset(-KBr, -H_(2)O)overset(alc.KOH)rarr underset(("Major 80%"))underset("But-2-ene")(H_(3)C - CH )=CH - CH_(3) + underset(("MINOR 20%"))underset("But-1-ene")(CH_(2) = CH - CH_(2)) - CH_(3)`


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