1.

Emf of hydrogen electrode in tern of pH is (at 1 atm pressure):

Answer»

`E_(H_(2)) = (RT)/(F) XX pH`
`E_(H_(2)) = (RT)/(F)(1)/(pH)`
`E_(H_(2)) = (2.303RT)/(F) pH`
`E_(H_(2)) = -0.0591 pH`

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