EMF of the cell, Ag|AgNO3(0.1M)|KBr(1N),AgBr(s)|Ag is −0.6 V at 298 – InterviewSolution

InterviewSolution

1.	EMF of the cell, Ag\|AgNO3(0.1M)\|KBr(1N),AgBr(s)\|Ag is −0.6 V at 298 KCalculate the Ksp of AgBr at 298 K.
Answer» EMF of the cell, $A g \| A g N O_{3} (0.1 M) \| K B r (1 N), A g B r (s) \| A g$ is $- 0.6 V$ at $298 K$ Calculate the $K_{s p}$ of $A g B r$ at $298 K$ .

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