1.

Emperical formula of compound is SF_(4). At 27^(@)C 0.1gm of gaseous compound occupies a volume of 22.2 ml and exert a pressure 1 atm. What is molecular formula of gas. [Take R=0.08atm lit k^(--1) "mol"^(-1)]

Answer»

`SF_(4)`
`S_(2)F_(8)`
`S_(3)F_(12)`
`S_(4)F_(6)`

SOLUTION :PV=nRT M.F= `(SF_(4))_(X)`
`(1.02)xx22xx10^(-3)`
`(0.1)/((108)x)xx0.0821xx293`
`x=(0.1xx0.0821xx293)/((108)(1.02)(22.1)xx10^(-3))=1`
M.F. `=SF_(4)`


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