1.

Empirical formula of a compound is CH_(2)O and its vapourdensity is 30. Molecular formula of the compound is

Answer»

`C_(3)H_(6)O_(3)`
`C_(2)H_(4)O_(2)`
`C_(2)H_(4)O`
`CH_(2)O`

Solution :Empirical Formula `= CH_(2)O`
Empirical formula mass `= 12 + 12 + 16 = 30`
Mol.Mass`= 2 xx V.D. = 2 xx 30 = 60`
`n = ("Mol.mass")/(" Empirical mass") = 60/30= 2`
Molecular formula `= (" Empirical formula")_(n)`
`= (CH_(2)O)_(2) = C_(2)H_(4)O_(2)`.


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