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Empirical formula of a compound is `CH_(2)O` and its vapour density is 30. Molecular formula of the compound isA. `C_(2)H_(6)O_(3)`B. `C_(2)H_(4)O_(2)`C. `C_(2)H_(4)O`D. `CH_(2)O` |
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Answer» Correct Answer - B Empirical formula `=CH_(2)O` Empirical formula mass `=12+2+16=30` Mol. Mass `2xxV.D.=2xx30=60` `n=(Mol. mass)/("Emperical mass")=(60)/(32)=2` Molecular formula`=(` emperical formula`)_(n)` `=(CH_(2)O)_(2)=C_(2)H_(4)O_(2)` |
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