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Empirical formula of a compound is `CH_(2)O` and its vapour density is `30`. Molecular formula of the compound isA. `C_(3)H_(6)O_(3)`B. `C_(2)H_(4)O_(2)`C. `C_(2)H_(4)O`D. `CH_(2)O` |
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Answer» Correct Answer - B Empirical Formula `= CH_(2)O` Empirical formula mass `= 12 + 12 + 16 = 30` Mol.Mass `= 2 xx V.D. = 2 xx 30 = 60` `n = ("Mol.mass")/(" Empirical mass") = 60/30= 2` Molecular formula `= (" Empirical formula")_(n)` `= (CH_(2)O)_(2) = C_(2)H_(4)O_(2)`. |
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