Saved Bookmarks
| 1. |
Employing the uncertainty principle, estimate the minimum kinetic energy of an electron confined within a region whose sizes is l=0.20nm. |
|
Answer» Solution :Clearly `Deltax le L" so" DELTA p_(x),ge(ħ)/(l)` Now `p_(x)geDeltaP_(x)` and so `T=(p_(x)^(2))/(2m) ge (ħ^(2))/(2ML^(2))` Thus `T_(min)=(ħ^(2))/(2m l^(2))~=0.95eV` |
|