1.

Empricial formula of a compound is CH_(2)O and its molecular mass is 90, the molecular formula of the compound is

Answer»

`C_3H_6O_3`
`C_2H_4O_2`
`C_6H_12O_6`
`CH_2O`

Solution :Emprical formula MASS , `CH_2O = 12 + 2 + 16 = 30`
MOLECULAR mass = 90
N = molecular mass/emprical formula mass
` = 90/30 = 3`
molecular formula ` = (CH_2O)_3 = C_3H_6O_3` .


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