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Emulsification of 10 mL of oil in water produces 2.4 xx10^(18) droplets. If the surface tension at the oil water interface is 0.03 J m^(-2)and area of each droplet is 12.5 xx10^(-6)m^(2), calculate the energy spent in the formation of oil droplets. |
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Answer» Solution :TOTAL droplets `=2.4 xx10^(18)` Total area = Total no. of droplets `xx` Area of each drop `=(2.4xx10^(18))xx(12.5xx10^(-16))=12.5xx2.4xx10^(2)m^(2)` Total energy CONSUMED in the fomation of droplets `=(0.03Jm^(-2))xx(12.5xx2.4xx10^(2)m^(2))=90J` |
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