Energy corresponding to threshold frequency of metal is 6.2 eV.For given radiation stopping potential is 5 V then incident radiation will be in …region.

Energy corresponding to threshold frequency of metal is 6.2 eV.For giv

1.	Energy corresponding to threshold frequency of metal is 6.2 eV.For given radiation stopping potential is 5 V then incident radiation will be in …region.
Answer» X-ray ultraviolet infrared visible Solution :`E=K_(m)+PHI=eV_(0)+phi=(5+6.2)EV=11.2 eV` `(hc)/(lambda)=11.2xx1.6xx10^(-19)J` `therefore lambda =(6.62xx10^(-34)xx3xx10^(8))/(11.2xx1.6xx10^(-19))` `=1.108xx10^(-7)m=1108 Å` This WAVELENGTH is in ultraviolet REGION.

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Energy corresponding to threshold frequency of metal is 6.2 eV.For given radiation stopping potential is 5 V then incident radiation will be in …region.

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