1.

Energy in the ground state of hydrogen atom is -13.6 eV. What is the energy in the first excited state ?

Answer»



SOLUTION :Energy of hydrogen ATOM in NTH orbit is
`E=-(13.6)/(n^(2))eV`
For Ist excited STATE, `n=2`
`E=-(13.6)/(4)=-3.4 eV`


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