1.

Energy is being emitted from the surface of a black body at 127^(@)C temperature at 1xx10^(6)" J s"^(-1)"m"^(-2). Temperature of the black body at which the rate of emission is 16xx10^(6)"J s"^(-1)"m"^(-2) will be :

Answer»

`254^(@)C`
`508^(@)C`
`527^(@)C`
`272^(@)C`.

Solution :`(E_(2))/(E_(1))=((T_(2))/(T_(1)))^(4)`
`(16xx10^(6))/(1xx10^(6))=((T_(2))/(400))`
`2=((T_(2))/(400))rArrT_(2)=800K=527^(@)C`
Thus CORRECT choice is (c ).


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