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Energy is being emitted from the surface of a black body at 127^(@)C temperature at 1xx10^(6)" J s"^(-1)"m"^(-2). Temperature of the black body at which the rate of emission is 16xx10^(6)"J s"^(-1)"m"^(-2) will be : |
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Answer» `254^(@)C` `(16xx10^(6))/(1xx10^(6))=((T_(2))/(400))` `2=((T_(2))/(400))rArrT_(2)=800K=527^(@)C` Thus CORRECT choice is (c ). |
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