1.

Energy of 1photon of gamma rays having wavelength of 2.5xx10^(-13)m will be how many times energy of radiation having wavelength of 5000 Å

Answer»

`2XX10^(6)`
`4xx10^(6)`
`8xx10^(6)`
`0.5xx10^(6)`

Solution :Let energy of photon of `lambda_(1)=2.5xx10^(-13)m` is N TIMES energy of photon of `lambda_(2)5000xx10^(-10)m` wavelength,
`therefore (HC)/(lambda_(1))=n(hc)/(lambda_(2))`
`therefore n=(lambda_(2))/(lambda_(1))=(5000xx10^(-10))/(2500xx10^(-16))`
`therefore n=2xx10^(6)`


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