1.

Energy of all molecules of a monatomic gas having a volume V and pressure P is 3//2PV. The total translational kinetic energy of all molecules of a diatomic gas at the same volume and pressure is

Answer»

`1//2PV`
`3//2PV`
`5//2PV`
`3PV`

Solution :ENERGY of 1 mol of GAS = `(f)/(2)RT=(f)/(2)PV`
where f = degrees of freedom
Montomic or diatomic GASES posses equal degree of freedom for translational MOTION and that is equal to 3, i.e., `f=3`
`therefore E=(3)/(2)PV`
Although TOTAL energy will be different
For monatomic gas, `E_("total")=(3)/(2)PV""("As" f=3)`
For diatomic gas, `E_("total")=(5)/(2)PV""("As" f=5)`


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