1.

Energy of an electron in an excited state of hydrogen atom is - 3.4 eV. Its angular momentum will be

Answer»

`1.11 XX 10^(-34)` JS
`1.51 xx 10^(-34) Js`
`2.11 xx 10^(-34) Js`
`3.72 xx 10^(-34) Js`

Solution :EnergyE = 3.4 eV correponds to n = 2 state of hydrogen atom hence its angularmomentum `= (NH)/(2pi)=(2xx6.63 xx 10^(-34))/(3xx3.14) = 2.11 xx 10^(-34)Js`.


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