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Energy of an electron is given byE=-2.178xx10^(-18)J((Z^(2))/(n^(2))). Wavelength of light requiredto excite an electron in an hydrogen atom from level n=1 to n=2 will be:

Answer»

`1.214xx10^(-7)m`
`2.816xx10^(-7)m`
`6.500xx10^(-7)m`
`8.500xx10^(-7)m`

Solution :`E_(1)=-2.178xx10^(-18)xx(1^(2))/(1^(2))=-2.178xx10^(-18)J`
`E_(2)=-2.178xx10^(-18)xx(1^(2))/(2^(2))=-5.445xx10^(-19)J`
ENERGY required to excite electron from level n=1 to n=2
`DeltaE=-5.445xx10^(-19)-(-2.178xx10^(-18))`
`=16.335xx10^(-19)J`
`(hc)/(lamda)=16.335xx10^(-19)`
or `lamda=(6.63xx10^(-34)xx3.0xx10^(8))/(16.335xx10^(-19))`
`=1.217xx10^(-7)m`


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