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Energy of electron in 2nd Bohr orbit of H-atomis(1)-5.44 x 10-19 Joule(2)-5.44 × 10-19 KJ(3)-5.44 x 10-19 Calorie(4)-5.44 × 10-19 eV |
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Answer» option A is correct in 2nd orbit the energy is -3.4eV 1 electronvolt= 1.602 × 10-19joule so, in joules it is ..... -3.4*(1.602× 10^-19) = -5.44× 10^-19 j |
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