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Energy of the electron in `nth` orbit of hydrogen atom is given by `E_(n) =-(13.6)/(n^(2))eV`. The amount of energy needed to transfer electron from first orbit to third orbit isA. `13.6 eV`B. `3.4 eV`C. `12.09 eV`D. 1.51 eV` |
Answer» Correct Answer - C For `n = 1, E_(1) = - (13.6)/((1)^(2)) = - 1.51 eV` and for `n = 3, E_(3) = - (13.6)/((3)^(2)) = - 1.51 eV` So required energy `= E_(3) - E_(!) = - 1.51 - (-13.6) = 12.09 eV` |
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