1.

Energy required for the electron excitation in Li^(++) from the first to the third Bohr orbit is

Answer»

`12.1` eV
`36.3` eV
`108.8` eV
`122.4` eV

Solution :`E_(N) =(-13.6)(Z^(2))/(n^(2))`
`Delta E = E_(3) - E_(2) = 13.6(3)^(2)[(1)/(1^(2)) - (1)/(3^(2))]`
` = (13.6 xx 9 xx 8)/(9) = 108.8 eV`


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