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Enthalpies of formation of `CO(g), N_(2)O(g)` and `N_(2)O_(4)(g)` are -110, -393, 81 and `9.7 kJ mol^(-1)` respectively . Find the value of `Delta_(r)H` for the reaction`:` `N_(2)O_(4)(g)+3CO(g) rarr N_(2)O(g) +3CO_(2)(g)` |
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Answer» `Delta_(r)H = Sigma Delta_(f)H(`Products) `-Sigma Delta_(f)H(` Reactants) `= [ Delta _(f) H( N_(2)O) +3Delta_(f)H(CO_(2))]- [ Delta_(f)H(N_(2)O_(4)) +3Delta_(f) H(CO)]` `= [8] +3 ( -393)] - [9.7 +3( -110) ] kJ = -777.7 kJ` |
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