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Enthalpy change for the reaction `2H(2)(g)rarr4H(g)` is `-869.6kJ` The dissociation energy of `H--H`bond is:A. `+217.4 kJ`B. `-431.8 kJ`C. `-869.6kJ`D. `+434.8 kJ` |
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Answer» Correct Answer - B `2H_(2)(g)to4H(g)`, `DeltaH=869.6 kJ` or `H_(2)(g)to2H(g)`, `DeltaH=+(869.6)/(2)` `=434.8 kJ` |
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