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Enthalpy change for the reaction `2H(2)(g)rarr4H(g)` is `-869.6kJ` The dissociation energy of `H--H`bond is:A. `+434.8 kJ`B. `+217.4 kJ`C. `434.8 kJ`D. `869.6 kJ` |
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Answer» Correct Answer - C `4H(g)to2H_(2)` , `DeltaH=-869.6 kJ` `4H_(2)to4(g)`, `DeltaH=869.6 kJ` `H_(2)to2H(g)` , `DeltaH=(869.6)/(2)=438.8 kJ` |
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