1.

Enthalpy change for the reaction , `4H(g) rarr 2H_(2)(g)`is`-869.6 kJ`. The dissociation energy of `H-H` bondisA. `+217 .4kJ`B. `-434.8 kJ`C. `-869.6kJ`D. `+ 434.8kJ`

Answer» Correct Answer - D
`2H_(2)(g) rarr 4H(g), DeltaH = +869.6kJ`
or `H_(2)(g) rarr 2H(g), DeltaH= + ( 869.6)/( 2) Kj`
`=434.8 kJ`


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