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Enthalpy change for the reaction `4H(g)rarr2H_2(g)` is `-869.6kJ` The dissociation energy of `H-H` bond is:A. `=217.4KJ`B. `-434.8KJ`C. `-869.6KJ`D. `+434.8KJ` |
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Answer» Correct Answer - D `2H_(2)(g)rarr4H(g),DeltaH=+869.6KJ` `H_(2)(g)rarr2H(g),DeltaH=(869.6KJ)/(2)=434.8KJ` . |
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