1.

Enthalpy change , when 1 g water is frozen at 0(@)C is (DeltaH_("fus")= 1.435 kcal mol ^(-1) )

Answer»

0.0797 KCAL
`-0.0797 kcal`
1.435 kcal
`- 1.435 kcal`

SOLUTION :`DeltaH=-1.435/18kcal G^(-1)`
`0.0797 kcal g^(-1)`


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