1.

Enthalpy of neutralization of acetic acid by NaOH is -50.6 kJ//"mol". And the heat of neutralisation of a strong acid with a strong base is -55.9 kJ/mol. What is the value of DeltaH for the ionisation of CH_(3)COOH

Answer»

`+5.3 kJ//mol`
`+6.2 kJ//mol`
`+8.2 kJ//mol`
`+9.3 kJ//mol`

SOLUTION :`DELTAH=DeltaH_("ioniz")+DeltaH_("NEU")=-50.6=DeltaH_("ioniz")+(-55.9)`
`DeltaH_("ioniz")=+5.3 kJ//mol`.


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