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Enthalpy of neutralization of `H_(3)PO_(3) "with " NaOH " is" -106.68 "kJ"//"mol"`. If enthalpy of neutralization of HCL with NaOH is -55.84`"kJ"//"mole"`, then calculate enthalpy of ionization of `H_(3)PO_(3)` in to its ions in kJ.A. 50.84 kJ`//`molB. 5 kJ`//`molC. 2.5 kJ`//`molD. None of these |
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Answer» Correct Answer - B |
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