Enthalpy of solution of `NaCl(s)` is`+ 4kJ mol^(-1)` and enthalpy of hydration is -784kJ `mol^(-1)`. Lattice enthalpy of NaCl(s) will be `"…..............." kJ mol^(-1)`

Enthalpy of solution of `NaCl(s)` is`+ 4kJ mol^(-1)` and enthalpy of h

1.	Enthalpy of solution of `NaCl(s)` is`+ 4kJ mol^(-1)` and enthalpy of hydration is -784kJ `mol^(-1)`. Lattice enthalpy of NaCl(s) will be `"…..............." kJ mol^(-1)`
Answer» `+ 788kJ mol^(-1)( Delta_("sol") H = Delta_("lattice")H + Delta_(hyd) H ) `

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Enthalpy of solution of `NaCl(s)` is`+ 4kJ mol^(-1)` and enthalpy of hydration is -784kJ `mol^(-1)`. Lattice enthalpy of NaCl(s) will be `"…..............." kJ mol^(-1)`

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