1.

Enthalpy of vaporization of benzene is +35.3 kJ mol^(-1) at its boiling point, 80^(@)C. The entopy change in the transition of the vapour to liquid at its boiling point [in JK^(-1)mol^(-1)] is….

Answer»

`-441`
`-100`
`+441`
`+100`

SOLUTION :Accordin to Gibb's formula, `DeltaG=DeltaH-TDeltaS`
At equilibrium, `DeltaG=0`
And entropy decreases on going from VAPOUR to liquid, i.e.,
`DeltaH=TDeltaS`
`DELTAS=-(DeltaH)/(T)=-(35300)/(80+273)=-100 JK^(-1)MOL^(-1)`


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