1.

Entropy changes for the process, H_(2)O_((l))rarrH_(2)O_((s)) at normal pressure and 274 K are given below DeltaS_("system")=-22.13, DeltaS_("surr")=+22.05,the process is non-spontaneous because

Answer»

`DeltaS_("SYSTEM") " is " -ve`
`DeltaS_("surr")" is +ve"`
`DeltaS_(U)" is -ve"`
`DeltaS_("system")ne DeltaS_("surr")`

Solution :`DeltaS_(u)=DeltaS_("system")+DeltaS_("SURROUNDING")=-22.13+22.05 =-0.08`
For a spontaneous process, `DeltaS_(u)` MUST be positive i.e.,
`DeltaS_(u)=DeltaS_("system")+DeltaS_("surrounding")gt0`.


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