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Equal currents each 'i' are flowing in three infinitely long wires along positive x,y and z axes, Find the magnetic field at the point (0,0,-a), |
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Answer» Solution :`bar(B)` due to in x - direction `vec(B)_(x) = (mu_0i)/(2 pia) hatj` `BARB` due to current in y -direction `barB_y = (mu_0i)/(2pia)(- HATI)` `barB` due to current in Z-direction is ZERO since the point is present on the line of the current CARRYING conductor. `B_Z = 0` `bar (B) = bar(B_x) + bar(B_y) + bar(B_z)` `bar(B)_("(0,0,a)")= (mu_0i)/(2pia) hatj - (mu_0i)/(2pia)hati` `|barB_("(0,0,-a)")|=(mu_0i)/(2pia) sqrt(2)` `|barB| = (mu_0i)/(2pia)sqrt(2)` |
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