1.

Equal volume of 0.02 M NH_(3)OH is mixed with 0.02 M HCI. Calculate [NH_(4)OH] at equivalence point : K_(b)[NH_(4_OH)]=10^(-5)

Answer»

`1.414xx10^(-3.5)`
`(1.414)/(3.16)xx10^(-5)`
`3.16xx10^(-5)`
`3.16xx10^(-6)`

ANSWER :d


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