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Equal volumes of 0.1M AgNO_(3) and 0.2M NaCI are mixed. The concentration of NO_(3)^(-) ions in the mixture will be |
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Answer» `0.1M` `0.1M AgNO_(3)` reacts with `0.1M NaCI` to produce `0.1M AgCI` and `0.1M NaNO_(3)` `:. NO_(3)^(-) = (0.1M)/(2) = 0.05M` `[ :'` When EQUAL volumes are mixed dilution occurs] |
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