1.

Equal volumes of following solutions are mixed, in which case the pH of resulting solution will be average value of pH of two solutions.

Answer»

pH=2 HCl and pH=12 NaOH
pH=2 HCl and pH=4 HCl
pH=2 HCN and pH= 12 NaOH (`k_a` for HCN=`10^(-10)`)
pH=5 `CH_3COOH` and pH=9 `NH_(3(AQ.)),K_a(CH_3COOH)=K_b(NH_(3_(aq)))`

Solution :(A)`pH=2 HCl` so [HCl]=`10^(-2)`
pH=12 NaOH so [NaOH]=`10^(-2)`
HENCE pH of mixture =7 (neutral )
(D)pH=5 `CH_3COOH` and pH=9 `NH_3` (aq), both must be of equal concentrations as `pK_a=pK_b`.Hence pH=pOH only if concentration are equal so on mixing equal volume we will get `CH_3COONH_4` salt solution and its pH is given is given by
`pH=1/2(pK_w+pK_a-pK_b)=7`


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