1.

Equal volumes of the following Ca^(2+) and F^(-) solutions are mixed. In which of the solutions will precipitations occur ? [K_(sp) of CaF_(2)=1.7 xx 10^(-10)] 1. 10^(-2) M Ca^(2+)+10^(-5)MF^(-) 2. 10^(-3) M Ca^(2)+10^(-3)MF^(-) 3. 10^(-4) MCa^(2)+10^(-2)MF^(-) 4. 10^(-2) MCa^(2)+10^(-3)MF^(-) Select the correct answer using the codes given below

Answer»

In 4 only
In 1 and 2
In 3 and 4
In 2,3 and 4

Solution :In case I
`[Ca^(2+)]` in reaction mixture `=0.5 xx 10^(-2)M`
`[F^(-)]` in reaction mixture `=0.5 xx 10^(-5)M`
`:. ` Ionic product
`=[Ca^(2+)][F^(-)]^(2)=(0.5 xx 10^(-2))xx (0.5 xx10^(-5))^(2)`
`=125 xx 10^(-15)=1.25 xx 10^(-13)xx1.7 xx 10^(-10)`
`:. `No. ppt is formed in this case
In case 2
`[Ca^(2+)]` in reaction mixture `=0.5 xx 10^(-3)M`
`[F^(-)]` in reaction mixture `=0.5 xx 10^(-3)M`
`:. `Ionic product `=(0.5 xx 10^(-3))(0.5 xx 10^(-3))^(2)`
`=125 xx 10^(-12)=1.25 xx 10^(-10)lt 1.7 xx 10^(-10)`
No. ppt. is formed in this case
In case 3
`[Ca^(2+)]` in reaction mixture `=0.5 xx 10^(-4)M`
`[F^(-)]` in reaction mixture `=0.5 xx 10^(-2)M`
`:. ` Ionic product `=[Ca^(2+)]xx[F^(-)]^(2)`
`=[0.5 xx 10^(-4)] xx [0.5 xx 10^(-2)]^(2)`
`=125 xx 10^(-11)`
`=1.25 xx 10^(-9) gt 1.7 xx 10^(-10)`
Thus a ppt. of `CaF_(2)` will be formed
In case 4
`[Ca^(2+)]` in reaction mixture `=0.5 xx 10^(-2)M`
`[F^(-)]`in reaction mixture `=0.5 xx 10^(-3)M`
Ionic product `[Ca^(2+)][F^(-)]^(2)`
`=[0.5 xx 10^(-2)][0.5 xx 10^(-3)]^(2)=125 xx 10^(-11)`
`=1.25 xx 10^(-9) gt 1.7 xx 10^(-10)`
Thus a ppt of `CaF_(2)` will be formed.


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