1.

Equal volumes of three acid solutions of PH 1,2 and 3 are mixed in a vessel. What will be the H^+ ion concentration in the mixture?

Answer»

`3.7 times 10^-2`
`10^-6`
0.111
none of these

Solution :`PH=-log_10[H^+]`
`therefore[H^+]=10^(-ph)`
LET the VOLUME be x mL
`V_1M_1+V_2M_2+V_3M_VM`
`thereforexmL of 10^-1 M+xmL of 10^-2 M+xL of 10^-3M`
`=3xmL of [H^+]`
`therefore[H^+]=(x[0.1+0.01+0.001])/3=(0.1+0.01+0.001)/3=0.111/3`
`=0.037=3.7 times 10^-2`


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