1.

Equal volumes of three acid solutions of pH 3, 4 and 5 are mixed in a vessel. What will be the H^(+) ion concentration in the mixture ?

Answer»

`1.11xx10^(-4)M`
`3.7xx10^(-4)M`
`3.7xx10^(-3)M`
`1.11xx10^(-3)M`

Solution :`[H_(3)O]^(+)` for a solution having PH=3 is GIVEN by
`[H_(3)O]^(+)=1xx10^(-3)` MOLES/litre
`[therefore [H_(3)O]=10^(-pH)`]
SIMILARLY for solution having pH=4,
`[H_(3)O]^(+)=1xx10^(-4)` moles/litre and for pH=5
`[H_(3)O^(+)]=1xx10^(-5)` moles/litre
Let the volume of each solution in mixture be 1L, then total volume of mixture solution L=(1+1+1)L=3L Total `[H_(3)O]^(+)` ion PRESENT in mixture solution `=(10^(-3)+10^(-4)+10^(-5)` moles
Then `[H_(3)O]^(+)` ion concentration of mixture solution
`=(10^(-3)+10^(-4)+10^(-5))/(3)M=(0.00111)/(3)M`
`=0.00037 M=3.7xx10^(-4)M`


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