1.

Equal volumes of three acid solutions of pH 3, 4and 5 are mixed in a vessel. What will be the H^+ ion concentration in the mixture?

Answer»

`3.7xx10^(-3)` M
`1.11xx10^(-3)` M
`1.11xx10^(-4)` M
`3.7xx10^(-4)` M

Solution :pH=-log `[H^+]`
`[H^+]=10^(- pH)` , `[H^+]` of SOLN. 1= `10^(-3)`
`[H^+]` of soln. 2= `10^(-4)` , `[H^+]` of soln. 3= `10^(-5)`
Total concentration of `[H^+] = 10^(-3) (1+1xx10^(-1) + 1xx10^(-2))`
`10^(-3) (1/1+1/10 +1/100) rArr 10^(-3) ((100+10+1)/100)`
`rArr 10^(-3) (111/100) = 1.11xx10^(-3)` M
So, `H^+` ION concentration in MIXTURE of equal mixture of these acid solution `= (1.11xx10^(-3))/3 = 3.7xx10^(-4)` M


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