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Equal volumes of three liquids of densities `rho_1`,`rho_2` and `rho_3`, specific heat capacities `c_1,c_2` and `c_3` and temperatures `t_1,t_2` and `t_3`, respectively are mixed together. What is the temperature of the mixture? Assume no changes in volume on mixing. |
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Answer» Let t be the temperature of the mixture. Net loss of heat by all `=(vrho_1)c_1(t_1-t)+(Vrho_2)c_2(t_2-t)+(Vrho_3)c_3(t_3-t)` but net loss`=0` `Vrho_1c_1(t_1-t)+Vrho_2c_2(t_2-t)+Vrho_3c_3(t_3-t)=0` or `t=(rho_1c_1t_1+rho_2c_2t_2+rho_3c_3t_3)/(rho_1c_1+rho_2c_2+rho_3c_3)` |
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