1.

Equation for the half period in first order reaction is

Answer»

`t_(1//2)=(0.602)/K`
`t_(1//2)=0.693/k`
`t_(1//2)=k/0.693`
`t_(1//2)=k/0.602`

SOLUTION :DERIVE `t_(1//2)` from KT = `2.303 LOG. (a) /(a-x)`


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