Equation of a bisector of the angle between the line y-b=(2m)/(1-m^2)( – InterviewSolution

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1.	Equation of a bisector of the angle between the line y-b=(2m)/(1-m^2)(x-a) and y-b=(2m')/(1-m^2)(x-a) is
Answer» (y-b)(m+m ')+(x-a)(1-mm ')=0 (y-b)(m-m ')+(x-a)(1-mm ')=0 (y-b)(m+m ')-(y-b)(1-mm ')=0 (y-b)(m+m ')+(y-b)(1-mm ')=0 Answer :(y-b)(1-mm')-(x-a)(m+m')=0

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