Equation of a line having slope 3 and the point (3, 2) lies on the lin

1.	Equation of a line having slope 3 and the point (3, 2) lies on the line 1. 3y - x - 3 = 02. y - 3x + 7 = 03. y + 3x - 11 = 04. 3y + x - 9 = 0
Answer» Correct Answer - Option 2 : y - 3x + 7 = 0 Concept: The general equation of a line is y = mx + c where m is the slope and c is any constant Slope of parallel lines are equal. Slope of perpendicular line have their product = -1 Equation of a line with slope m and passing through (x1, y1) (y - y1) = m (x - x1) Equation of a line passing through (x1, y1) and (x2, y2) is: \(\rm {y-y_1\over x-x_1}={y_2-y_1\over x_2-x_1}\) Calculation: Given the line has the slope 3 and passes through (3, 2) ∴ Equation of the line is (y - y1) = m (x - x1) ⇒ y - 2 = 3 (x - 3) ⇒ y - 3x + 7 = 0

Equation of a line having slope 3 and the point (3, 2) lies on the line 1. 3y - x - 3 = 02. y - 3x + 7 = 03. y + 3x - 11 = 04. 3y + x - 9 = 0

Answer» Correct Answer - Option 2 : y - 3x + 7 = 0

Concept:

The general equation of a line is y = mx + c

where m is the slope and c is any constant

Equation of a line with slope m and passing through (x1, y1)

(y - y1) = m (x - x1)

Equation of a line passing through (x1, y1) and (x2, y2) is:

\(\rm {y-y_1\over x-x_1}={y_2-y_1\over x_2-x_1}\)

Calculation:

Given the line has the slope 3 and passes through (3, 2)

∴ Equation of the line is

(y - y1) = m (x - x1)

⇒ y - 2 = 3 (x - 3)

⇒ y - 3x + 7 = 0