Equilibirum constants `K_(1)` and `K_(2)` for the following equilibria `NO(g) + (1)/(2)O_(2)hArrNO_(2)(g)` and `2NO_(2)(g)hArr` `2NO(g) + O_(2)(g)` are related asA. `K_(2)= (1)/(K_(1)^(2))`B. `K_(2) = (1)/(K_(1))`C. `K_(2) = K_(1)^(2)`D. `K_(2) = (K_(1))/(2)`

Equilibirum constants `K_(1)` and `K_(2)` for the following equilibria

1.	Equilibirum constants `K_(1)` and `K_(2)` for the following equilibria `NO(g) + (1)/(2)O_(2)hArrNO_(2)(g)` and `2NO_(2)(g)hArr` `2NO(g) + O_(2)(g)` are related asA. `K_(2)= (1)/(K_(1)^(2))`B. `K_(2) = (1)/(K_(1))`C. `K_(2) = K_(1)^(2)`D. `K_(2) = (K_(1))/(2)`
Answer» Correct Answer - A `K_(1) = ([NO_(2)])/([NO][O_(2)])` and `K_(2) = ([NO]^(2)[O_(2)])/([NO_(2)]^(2))` If eqn. is multiplied by n, then new equilibrium constant is `K_(1)n` and if equ. Is reversed, then new equilibrium constant is reciprocal of pervious. `:. K_(2) = (1)/(K_(1)^(2))`

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Equilibirum constants `K_(1)` and `K_(2)` for the following equilibria `NO(g) + (1)/(2)O_(2)hArrNO_(2)(g)` and `2NO_(2)(g)hArr` `2NO(g) + O_(2)(g)` are related asA. `K_(2)= (1)/(K_(1)^(2))`B. `K_(2) = (1)/(K_(1))`C. `K_(2) = K_(1)^(2)`D. `K_(2) = (K_(1))/(2)`

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