Equilibrium concentration of HI, I_(2) and H_(2) is 0.7, 0.1 and 0.1 m – InterviewSolution

1.	Equilibrium concentration of HI, I_(2) and H_(2) is 0.7, 0.1 and 0.1 moles/litre. Calculate the equilibrium constant for the reaction : I_(2(g))+H_(2(g))hArr2HI_((g))-
Answer» 0.36 36 49 0.49 Answer :C

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