1.

Equilibrium concentration of HI,I_(2) and H_(2) is 0.7, 0.1 and 0.1 M respectively. The equlibrium constant for the reaction I_(2)+H_(2)hArr2HIis

Answer»

36
49
`0.49`
`0.36`

SOLUTION :`K_(C)=([HI]^(2))/([H_(2)][I_(2)])=([0.7]^(2))/([0.1][0.1])=49`


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