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Equilibrium concentration of `HI,I_(2) and H_(2)` is 0.7, 0.1 and 0.1 M respectively. The equlibrium constant for the reaction `I_(2)+H_(2)hArr2HIis`A. 36B. 49C. `0.49`D. `0.36` |
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Answer» Correct Answer - B `K_(c)=([HI]^(2))/([H_(2)][I_(2)])=([0.7]^(2))/([0.1][0.1])=49` |
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