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Equilibrium constant for the following equilibrium is given at `)^(@)C` . `Na_(2)HPO_(4)` . `12H_(2)O(s) hArrNa_(2)HPO_(4)` . `7H_(2)O(s) + 5H_(2)O(g)` `K_(p) = 31.25xx10^(-13)`. At equilibrium what will be partial pressure of water vapour: |
Answer» Correct Answer - `5xx10^(-3)` atm. `Na_(2)HPO_(4).12H_(2)O(S)hArrNa_(2)HPO_(4).7H_(2)O(S)+5H_(2)O(g) K_(P)=31.25xx10^(-13)` `K_(P)=(P_(H_(2)O))^(5)` `=(P_(H_(2)O))^(5)=31.25xx10^(-13)` `=(P_(H_(2)O))=(3125)^(1//5xx(10^(-10))^(1//5)` `(P_(H_(2)O))=5xx10^(-3)` |
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