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Equilibrium constant for the reaction: `H_(2)(g) +I_(2) (g) hArr 2HI(g) is K_(c) = 50 at 25^(@)C` The standard Gibbs free enegry change for the reaction will be:A. `-6.964kJ`B. `-9.694kJ`C. `-4.964kJ`D. `-6.496kJ` |
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Answer» Correct Answer - B `DeltaG^(@)=-2.303RT" log "K_(C)` `=-2.303xx8.314xx298" log "50` `=-9694J=-9.694kJ` |
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